因式分解计算题:
(1) X2y-Xy+3X-3 (2) Xy+2y+3X+6
详解:
(1) X2y-Xy+3X-3
= (X2y-Xy) +(3X-3) (分组)
= Xy(X-1)+3(X-1) (在 X2y-Xy中提出 Xy,3X-3中提出 3)
= (Xy+3)(X-1) (提出 X-1)
(2) Xy+2y+3X+6
= (Xy+2y)+ (3X+6) (分组)
= y(X+2)+3(X+2) (在Xy+2y中提出y,3X+6中提出3)
= (y+3)(X+2) (提出X+2)
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